An organic compound (A) (molecular formula C_ | vedclass

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(A) The organic compound $(A)$ with molecular formula $C_{6}H_{12}O_{2}$ is an ester. Upon hydrolysis with dil. $H_{2}SO_{4}$,it yields a carboxylic a

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(A) The organic compound $(A)$ with molecular formula $C_{6}H_{12}O_{2}$ is an ester. Upon hydrolysis with dil. $H_{2}SO_{4}$,it yields a carboxylic acid $(B)$ and an alcohol $(C)$. The alcohol $(C)$ gives immediate white turbidity with Lucas reagent (anhydrous $ZnCl_{2}$ and conc. $HCl$),which is a characteristic test for a tertiary alcohol. Among the given options,the ester that produces a tertiary alcohol (tert-butyl alcohol) upon hydrolysis is tert-butyl acetate. The structure shown in option $(A)$ corresponds to tert-butyl acetate,which hydrolyzes to form acetic acid and tert-butyl alcohol. Thus,the correct compound is $(A)$.

An organic compound $(A)$ (molecular formula $C_{6}H_{12}O_{2}$) was hydrolysed with dil. $H_{2}SO_{4}$ to give a carboxylic acid $(B)$ and an alcohol $(C).$ $C$ gives white turbidity immediately when treated with anhydrous $ZnCl_{2}$ and conc. $HCl$. The organic compound $(A)$ is

Similar Questions

Which of the following compounds are not oxidized by $HIO_4$?
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$(2)$ $CH_3-C(=O)-CHO$
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