Which of the following reagents limits the ox | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Primary alcohols $(R-CH_2OH)$ are oxidized to aldehydes $(R-CHO)$ and further to carboxylic acids $(R-COOH)$ by strong oxidizing agents.

Vedclass · Accepted Answer

$PCC$

Vedclass · Answer

(A) Step $1$: Primary alcohols $(R-CH_2OH)$ are oxidized to aldehydes $(R-CHO)$ and further to carboxylic acids $(R-COOH)$ by strong oxidizing agents.Step $2$: $K_2Cr_2O_7 / 	ext{dil. } H_2SO_4$ and acidic $KMnO_4$ are strong oxidizing agents that oxidize primary alcohols directly to carboxylic acids.Step $3$: $CrO_3$ in anhydrous conditions can stop at the aldehyde stage, but $PCC$ (Pyridinium chlorochromate) is specifically designed to oxidize primary alcohols to aldehydes without further oxidation to carboxylic acids.Step $4$: Therefore, $PCC$ is the correct reagent to limit the oxidation to the aldehyde stage.

Which of the following reagents limits the oxidation of $R-CH_2OH$ to $R-CHO$ only?

Similar Questions

Lucas test is used for:

$A$ compound with formula $C_4H_{10}O$ on oxidation gives $C_4H_8O$,which forms an oxime and gives a positive iodoform test. The original compound on reaction with concentrated $H_2SO_4$ gives $C_4H_8$. What is the structure of the compound?

Among the compounds $A$ and $B$ with molecular formula $C_9H_{18}O_3$,$A$ has a higher boiling point than $B$. The possible structures of $A$ and $B$ are

Which of the following compounds yields propanone upon dehydrogenation?

Consider the below reaction,and choose the correct statement:

Vedclass Test Series

Exam Paper Generator

Online Exam Module