An organic compound A on treatment with benze | vedclass

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Question

(D) The reaction of an organic compound $A$ with benzene sulphonyl chloride (Hinsberg's reagent) to form a product $B$ that is soluble in $NaOH$ indic

Vedclass · Accepted Answer

$C_6H_5-CH(CH_3)-NH_2$

Vedclass · Answer

(D) The reaction of an organic compound $A$ with benzene sulphonyl chloride (Hinsberg's reagent) to form a product $B$ that is soluble in $NaOH$ indicates that $A$ is a primary amine $(R-NH_2)$.Primary amines react with benzene sulphonyl chloride to form $N$-alkylbenzene sulphonamide,which contains an acidic hydrogen atom attached to the nitrogen,making it soluble in $NaOH$.Secondary amines form $N,N$-dialkylbenzene sulphonamides,which lack an acidic hydrogen and are insoluble in $NaOH$.Tertiary amines do not react with benzene sulphonyl chloride.Among the given options:$A$: $C_6H_5-N(CH_3)_2$ is a tertiary amine.$B$: $C_6H_5-NH-CH_2-CH_3$ is a secondary amine.$C$: $C_6H_5-CH_2-NH-CH_3$ is a secondary amine.$D$: $C_6H_5-CH(CH_3)-NH_2$ is a primary amine.Therefore,the correct compound is $C_6H_5-CH(CH_3)-NH_2$.

List-$I$ (Functional group)	List-$II$ (Functional group reagent)
$(a)$ Aliphatic Alcohol	$(i)$ Neutral ferric chloride test
$(b)$ $C_6H_5NH_2$	(ii) Azo dye test
$(c)$ $CH_3CH_2CHO$	(iii) Ceric ammonium nitrate test
$(d)$ Phenol	(iv) Tollen’s reagent test

An organic compound $A$ on treatment with benzene sulphonyl chloride gives compound $B$. $B$ is soluble in dil. $NaOH$ solution. Compound $A$ is:

Similar Questions

Which of the following amine$(s)$ show$(s)$ positive carbylamine test?
$A. CH_3CH_2NH_2$
$B. (CH_3)_2NH$
$C. CH_3NH_2$
$D. (CH_3)_3N$
$E. C_6H_5NH_2$
Choose the correct answer from the options given below:

Which of the following can be used to distinguish primary,secondary and tertiary amines?

Primary and secondary amines can be distinguished by

The element not present in Nessler's reagent is:

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