An unbiased coin is tossed n times. If the pr | vedclass

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(B) The probability of getting at least one head is given by $1 - P(	ext{no head})$.Since the coin is unbiased,the probability of getting no head in

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$3$

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(B) The probability of getting at least one head is given by $1 - P(	ext{no head})$.Since the coin is unbiased,the probability of getting no head in $n$ tosses is $\left(\frac{1}{2}ight)^n$.Therefore,the probability of getting at least one head is $1 - \left(\frac{1}{2}ight)^n$.According to the problem,$1 - \left(\frac{1}{2}ight)^n > 0.8$.This simplifies to $1 - 0.8 > \left(\frac{1}{2}ight)^n$,which means $0.2 > \left(\frac{1}{2}ight)^n$.Writing $0.2$ as $\frac{1}{5}$,we get $\frac{1}{5} > \frac{1}{2^n}$,which implies $2^n > 5$.For $n=1$,$2^1 = 2 For $n=2$,$2^2 = 4 For $n=3$,$2^3 = 8 > 5$.Thus,the least value of $n$ is $3$.

An unbiased coin is tossed $n$ times. If the probability of getting at least one head is greater than $0.8$,then the least value of $n$ is

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