An unbiased coin is tossed 8 times. The proba | vedclass

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(B) The total number of outcomes when a coin is tossed $8$ times is $2^8 = 256$. The event of obtaining at least one head and at least one tail is the

Vedclass · Accepted Answer

$\frac{127}{128}$

Vedclass · Answer

(B) The total number of outcomes when a coin is tossed $8$ times is $2^8 = 256$. The event of obtaining at least one head and at least one tail is the complement of the event of obtaining all heads or all tails. $P(	ext{All Heads}) = \frac{1}{2^8} = \frac{1}{256}$. $P(	ext{All Tails}) = \frac{1}{2^8} = \frac{1}{256}$. The probability of obtaining either all heads or all tails is $P(	ext{All Heads}) + P(	ext{All Tails}) = \frac{1}{256} + \frac{1}{256} = \frac{2}{256} = \frac{1}{128}$. Therefore,the required probability is $1 - \frac{1}{128} = \frac{127}{128}$.

An unbiased coin is tossed $8$ times. The probability of obtaining at least one head and at least one tail is

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