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(C) Let the intensity of the unpolarised incident light be $I_0$. After passing through the first polariser, the intensity becomes $I_1 = I_0 / 2$. Ac

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$4: 3$

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(C) Let the intensity of the unpolarised incident light be $I_0$. After passing through the first polariser, the intensity becomes $I_1 = I_0 / 2$. According to Malus' Law, the intensity of light emerging from a polariser is $I = I_{in} \cos^2 	heta$, where $	heta$ is the angle between the incident light's polarisation axis and the polariser's axis. For the second sheet, the angle between the first and second sheet is $	heta = 30^{\circ}$. Thus, $I_2 = I_1 \cos^2(30^{\circ}) = (I_0 / 2) 	imes (\sqrt{3} / 2)^2 = (I_0 / 2) 	imes (3 / 4) = 3I_0 / 8$. For the third sheet, the angle between the second and third sheet is also $	heta = 30^{\circ}$. Thus, $I_3 = I_2 \cos^2(30^{\circ}) = (3I_0 / 8) 	imes (3 / 4) = 9I_0 / 32$. The ratio of intensities emerging from the second and third sheets is $I_2 / I_3 = (3I_0 / 8) / (9I_0 / 32) = (3 / 8) 	imes (32 / 9) = 4 / 3$. Therefore, the ratio is $4: 3$.

An unpolarised beam of light is incident on a group of three polarising sheets arranged such that the angle between the axes of any two adjacent sheets is $30^{\circ}$. The ratio of the intensities of polarised light emerging from the second and third sheets is

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