An urn contains 10 green,12 yellow,and 11 whi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Total number of balls = $10 + 12 + 11 = 33$.Number of ways to select $2$ balls from $33$ is $^33C_2 = \frac{33 	imes 32}{2 	imes 1} = 528$.Numbe

Vedclass · Accepted Answer

$\frac{9}{16}$

Vedclass · Answer

(D) Total number of balls = $10 + 12 + 11 = 33$.Number of ways to select $2$ balls from $33$ is $^33C_2 = \frac{33 	imes 32}{2 	imes 1} = 528$.Number of balls that are not white = $10 + 12 = 22$.Number of ways to select $2$ balls such that none are white = $^22C_2 = \frac{22 	imes 21}{2 	imes 1} = 231$.Probability of selecting no white balls = $\frac{231}{528} = \frac{7}{16}$.Probability of selecting at least one white ball = $1 - P(	ext{no white ball}) = 1 - \frac{7}{16} = \frac{9}{16}$.

An urn contains $10$ green,$12$ yellow,and $11$ white balls. What is the probability that when $2$ balls are selected,at least one is white?

Similar Questions

$A$ letter is known to have come either from $LONDON$ or $CLIFTON$; on the postmark only the two consecutive letters $ON$ are legible. The probability that it came from $LONDON$ is

$A$ bag contains $5$ brown and $4$ white socks. $A$ man pulls out two socks. The probability that these are of the same colour is

The probability of $A, B, C$ solving a problem are $\frac{1}{3}, \frac{2}{7}, \frac{3}{8}$ respectively. If all the three try to solve the problem simultaneously,the probability that exactly one of them will solve it,is

Out of $40$ consecutive natural numbers,two are chosen at random. The probability that the sum of the numbers is odd is:

Find the chance of throwing $6$ at least once in six throws with a single die.

Vedclass Test Series

Exam Paper Generator

Online Exam Module