Analysis shows that nickel oxide has the form | vedclass

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Question

(D) Given the formula of nickel oxide is $Ni_{0.98}O_{1.00}$.Let the number of $Ni^{2+}$ ions be $x$ and the number of $Ni^{3+}$ ions be $(0.98 - x)$.

Vedclass · Accepted Answer

$Ni^{2+}=96 \%$ and $Ni^{3+}=4 \%$

Vedclass · Answer

(D) Given the formula of nickel oxide is $Ni_{0.98}O_{1.00}$.Let the number of $Ni^{2+}$ ions be $x$ and the number of $Ni^{3+}$ ions be $(0.98 - x)$.Since the total charge of the compound must be zero,the sum of positive charges equals the sum of negative charges.$2x + 3(0.98 - x) + 1(-2) = 0$$2x + 2.94 - 3x - 2 = 0$$-x + 0.94 = 0$$x = 0.94$So,the fraction of $Ni^{2+}$ ions $= \frac{0.94}{0.98} 	imes 100 \approx 96 \%$.The fraction of $Ni^{3+}$ ions $= \frac{0.98 - 0.94}{0.98} 	imes 100 = \frac{0.04}{0.98} 	imes 100 \approx 4 \%$.Therefore,the fractions are $Ni^{2+}=96 \%$ and $Ni^{3+}=4 \%$.

Analysis shows that nickel oxide has the formula $Ni_{0.98}O_{1.00}$. The fractions of $Ni^{2+}$ and $Ni^{3+}$ ions in the crystal are ......

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