The angle between the lines x = 2 and x - 3y | vedclass

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(B) The line $x = 2$ is a vertical line,so its slope $m_1$ is undefined (or $\infty$).The line $x - 3y = 6$ can be written as $3y = x - 6$,or $y = \fr

Vedclass · Accepted Answer

$	an^{-1}(3)$

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(B) The line $x = 2$ is a vertical line,so its slope $m_1$ is undefined (or $\infty$).The line $x - 3y = 6$ can be written as $3y = x - 6$,or $y = \frac{1}{3}x - 2$. The slope of this line is $m_2 = \frac{1}{3}$.The angle $	heta$ between a vertical line and a line with slope $m$ is given by $	an 	heta = \left| \frac{1}{m} ight|$.Here,$m = \frac{1}{3}$,so $	an 	heta = \left| \frac{1}{1/3} ight| = 3$.Therefore,$	heta = 	an^{-1}(3)$.

The angle between the lines $x = 2$ and $x - 3y = 6$ is

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