The lines a_1x + b_1y + c_1 = 0 and a_2x + b_ | vedclass

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(B) The equations of the lines are $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$.The slope of the first line is $m_1 = -\frac{a_1}{b_1}$.The slo

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$a_1a_2 + b_1b_2 = 0$

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(B) The equations of the lines are $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$.The slope of the first line is $m_1 = -\frac{a_1}{b_1}$.The slope of the second line is $m_2 = -\frac{a_2}{b_2}$.If the lines are perpendicular to each other,the product of their slopes must be $-1$,i.e.,$m_1 	imes m_2 = -1$.Substituting the values,we get $\left(-\frac{a_1}{b_1}ight) 	imes \left(-\frac{a_2}{b_2}ight) = -1$.$\Rightarrow \frac{a_1a_2}{b_1b_2} = -1$.$\Rightarrow a_1a_2 = -b_1b_2$.$\Rightarrow a_1a_2 + b_1b_2 = 0$.

The lines $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ are perpendicular to each other,if

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