The angle between the straight lines x - ysqr | vedclass

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(A) The given lines are $L_1: x - y\sqrt{3} = 5$ and $L_2: \sqrt{3}x + y = 7$.Comparing these with the general form $ax + by + c = 0$,the slopes are:F

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$90$

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(A) The given lines are $L_1: x - y\sqrt{3} = 5$ and $L_2: \sqrt{3}x + y = 7$.Comparing these with the general form $ax + by + c = 0$,the slopes are:For $L_1$,$m_1 = -\frac{1}{-\sqrt{3}} = \frac{1}{\sqrt{3}}$.For $L_2$,$m_2 = -\frac{\sqrt{3}}{1} = -\sqrt{3}$.Since $m_1 	imes m_2 = \left(\frac{1}{\sqrt{3}}ight) 	imes (-\sqrt{3}) = -1$,the product of the slopes is $-1$.Therefore,the lines are perpendicular to each other.The angle between them is $90^\circ$.

The angle between the straight lines $x - y\sqrt{3} = 5$ and $\sqrt{3}x + y = 7$ is ............. $^\circ$.

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