The angle between the two curves y^2 = 4(x + | vedclass

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(B) The given equations are $y^2 = 4(x + 1)$ and $x^2 = 4(y + 1)$.These represent two parabolas.The first parabola $y^2 = 4(x + 1)$ has its vertex at

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$90$

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(B) The given equations are $y^2 = 4(x + 1)$ and $x^2 = 4(y + 1)$.These represent two parabolas.The first parabola $y^2 = 4(x + 1)$ has its vertex at $(-1, 0)$ and opens to the right along the $x$-axis.The second parabola $x^2 = 4(y + 1)$ has its vertex at $(0, -1)$ and opens upwards along the $y$-axis.Since the axis of the first parabola is the $x$-axis and the axis of the second parabola is the $y$-axis,and these axes are perpendicular to each other,the angle of intersection between these two curves at their point of intersection is $90^\circ$.

The angle between the two curves $y^2 = 4(x + 1)$ and $x^2 = 4(y + 1)$ is .............. $^\circ$.

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