Angle of minimum deviation is equal to the ha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an equilateral prism, the prism angle $A = 60^\circ$.Given that the angle of minimum deviation $\delta_m = A/2 = 60^\circ / 2 = 30^\circ$.The

Vedclass · Accepted Answer

$\sqrt{2}$

Vedclass · Answer

(C) For an equilateral prism, the prism angle $A = 60^\circ$.Given that the angle of minimum deviation $\delta_m = A/2 = 60^\circ / 2 = 30^\circ$.The formula for the refractive index $\mu$ is given by $\mu = \frac{\sin((A+\delta_m)/2)}{\sin(A/2)}$.Substituting the values, we get $\mu = \frac{\sin((60^\circ + 30^\circ)/2)}{\sin(60^\circ/2)} = \frac{\sin(45^\circ)}{\sin(30^\circ)}$.Since $\sin(45^\circ) = 1/\sqrt{2}$ and $\sin(30^\circ) = 1/2$, we have $\mu = \frac{1/\sqrt{2}}{1/2} = \frac{2}{\sqrt{2}} = \sqrt{2}$.

Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is . . . . . . .

Similar Questions

When white light is passed through a prism, which colour shows the minimum deviation?

Find the value of the angle of emergence for an emergent ray from the prism in the figure given below. (Refractive index of the material of the prism is $\sqrt{3}$ and the refractive index of air is $1$) (in $^\circ$)

Monochromatic light passes through a prism. Compared to that in air, inside the prism the light's

The angles of incidence and emergence of a light ray passing through a prism of angle $A$ are $i$ and $e$ respectively. The total deviation produced by the prism is

Vedclass Test Series

Exam Paper Generator

Online Exam Module