Angular speed of the hour hand of a clock in degrees per second is:

Two cars of masses $m_{1}$ and $m_{2}$ are moving in circles of radii $r_{1}$ and $r_{2}$ respectively. Their angular speeds $\omega_{1}$ and $\omega_{2}$ are such that they both complete one revolution in the same time $t$. The ratio of the linear speed of $m_{1}$ to the linear speed of $m_{2}$ is:

As shown in the figure,a particle is moving with a constant speed $v = \pi \, m/s$ in a circular path. Considering its motion from point $A$ to point $B$,where the angle subtended at the center is $120^{\circ}$,the magnitude of the average velocity is:

$A$ particle is performing uniform circular motion along the circumference of a circle of diameter $1 \ m$ with a frequency of $4 \ Hz$. The acceleration of the particle in $m/s^2$ is (in $\pi^2$)

$A$ particle is performing $U.C.M.$ along a circle of radius $R$. In half the period of revolution, its displacement and distance covered are respectively

If $\omega_1$ is the angular velocity of the hour hand of a clock and $\omega_2$ is the angular velocity of the Earth,then the ratio $\omega_1 : \omega_2$ is