If $\omega_1$ is the angular velocity of the hour hand of a clock and $\omega_2$ is the angular velocity of the Earth,then the ratio $\omega_1 : \omega_2$ is

$A$ particle is moving on a circular path with a constant speed $v$. Its change of velocity as it moves from $A$ to $B$ in the figure is

$A$ body moves along a circular path of diameter $30 \text{ cm}$. It starts from one end of a diameter, moves along the circular path, and reaches the other end of the diameter in $3 \text{ seconds}$. The angular speed of the body in radians per second is:

The ratio of the angular velocity of the hour hand of a watch to the angular velocity of the rotation of the Earth is:

An object moves at a constant speed along a circular path in a horizontal plane with its centre at the origin. When the object is at $x = +2\,m$,its velocity is $-4 \hat{j}\,m/s$. The object's velocity $(v)$ and acceleration $(a)$ at $x = -2\,m$ will be

For a particle executing uniform circular motion: