The ratio of the angular velocity of the hour | vedclass

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(B) The angular velocity $\omega$ is given by $\omega = \frac{2\pi}{T}$,where $T$ is the time period.For the hour hand of a watch,the time period $T_h

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$2$:$1$

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(B) The angular velocity $\omega$ is given by $\omega = \frac{2\pi}{T}$,where $T$ is the time period.For the hour hand of a watch,the time period $T_h = 12 	ext{ hours}$.Thus,$\omega_h = \frac{2\pi}{12} 	ext{ rad/hour}$.For the rotation of the Earth,the time period $T_e = 24 	ext{ hours}$.Thus,$\omega_e = \frac{2\pi}{24} 	ext{ rad/hour}$.The ratio of the angular velocity of the hour hand to the angular velocity of the Earth is $\frac{\omega_h}{\omega_e} = \frac{2\pi/12}{2\pi/24} = \frac{24}{12} = 2:1$.

The ratio of the angular velocity of the hour hand of a watch to the angular velocity of the rotation of the Earth is:

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