Aniline on treatment with $NaNO_2 / HCl$ at about $0^\circ C$ gives a compound $A$, which on further treatment with $CuCN / KCN$ gives a compound $B$, which when reacts with $H_2 / Ni$ gives a compound $C$. The compound $C$ on reaction with $HNO_2$ gives a compound $D$. The structure of $D$ is:
- A$C_6H_5CH_2OH$
- B$C_6H_5NHCH_2CH_3$
- C$C_6H_5NHOH$
- D$C_6H_5CH_2NH_2$
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Similar Questions
The ammonolysis of alcohol is represented by the reaction $xCH_3OH + yNH_3 \xrightarrow[Al_2O_3/ThO_2]{300-400^{\circ}C} \text{Products}$. The products formed are:
Medium
View SolutionWhen you ingest aspirin,it passes through your stomach,which has an acidic $pH$,before traveling through the basic environment of your intestine. Provide the structure form as it exists in the intestine.
Difficult
View SolutionMatch the Compounds (List-$I$) with the appropriate Catalyst/Reagents (List-$II$) for their reduction or conversion into corresponding amines.
List-$I$ (Compounds)
List-$II$ (Catalyst/Reagents)
$A$. $R-CONH_2$
$I$. $NaOH$ (aqueous)
$B$. $C_6H_5NO_2$
$II$. $H_2 / Ni$
$C$. $R-C \equiv N$
$III$. $LiAlH_4, H_2O$
$D$. $N$-alkylphthalimide
$IV$. $Sn,HCl$
Choose the correct answer from the options given below:
| List-$I$ (Compounds) | List-$II$ (Catalyst/Reagents) |
| $A$. $R-CONH_2$ | $I$. $NaOH$ (aqueous) |
| $B$. $C_6H_5NO_2$ | $II$. $H_2 / Ni$ |
| $C$. $R-C \equiv N$ | $III$. $LiAlH_4, H_2O$ |
| $D$. $N$-alkylphthalimide | $IV$. $Sn,HCl$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2025
View SolutionConvert:
$(i)$ $3-$Methylaniline into $3-$nitrotoluene.
$(ii)$ Aniline into $1,3,5-$tribromobenzene.
$(i)$ $3-$Methylaniline into $3-$nitrotoluene.
$(ii)$ Aniline into $1,3,5-$tribromobenzene.
Difficult
View SolutionMatch the following:
List-$I$ List-$II$ $A$. Amide $I$. Carbylamine reaction $B$. Nitrile $II$. Hinsberg's reagent $C$. $C_6H_5SO_2Cl$ $III$. Hofmann's bromamide reaction $D$. $1^{\circ}$-Amine $IV$. $LiAlH_4$
| List-$I$ | List-$II$ |
|---|---|
| $A$. Amide | $I$. Carbylamine reaction |
| $B$. Nitrile | $II$. Hinsberg's reagent |
| $C$. $C_6H_5SO_2Cl$ | $III$. Hofmann's bromamide reaction |
| $D$. $1^{\circ}$-Amine | $IV$. $LiAlH_4$ |
DifficultTS EAMCET 2022
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