Aniline,when diazotized in cold and then treated with $N,N$-dimethylaniline,gives a coloured product. Its structure would be:

$A$ compound $X$ with formula $C_4H_{11}N$ reacts with $HNO_2$ to liberate nitrogen and produce compound $Y$. The compound $Y$ on treatment with $I_2 / NaOH$ produces a sodium salt of a carboxylic acid. The compound $X$ is

The mass of benzanilide obtained from the benzoylation reaction of $5.8 \ g$ of aniline, if the yield of product is $82\%$, is . . . . . . $g$ (nearest integer).
(Given molar mass in $g \ mol^{-1}$: $H: 1, C: 12, N: 14, O: 16$)

Given below are two statements:
Statement-$I$: In Hofmann degradation reaction,the migration of only an alkyl group takes place from carbonyl carbon of the amide to the nitrogen atom.
Statement-$II$: The group is migrated in Hofmann degradation reaction to an electron-deficient nitrogen atom.
In the light of the above statements,choose the most appropriate answer from the options given below:

Which one of the following gives the most stable diazonium salt?

What will be the products $A$,$B$,and $C$ in the following reaction sequence?
$\text{Phenol}$ $\xrightarrow[\text{Distillation}]{\text{Zn}} A$ $\xrightarrow[\text{conc. } H_2SO_4]{\text{conc. } HNO_3, 60^{\circ}C} B$ $\xrightarrow[\text{NaOH (aq)}]{\text{Zn}} C$