Arrange the acidity of the given four compoun | vedclass

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(B) The acidity of a compound depends on the stability of its conjugate base.$1.$ In $(I)$ $CH_3COCH_2COCH_3$ (acetylacetone),the protons on the centr

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$I > IV > II > III$

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(B) The acidity of a compound depends on the stability of its conjugate base.$1.$ In $(I)$ $CH_3COCH_2COCH_3$ (acetylacetone),the protons on the central carbon are highly acidic because the resulting carbanion is stabilized by resonance with two carbonyl groups (active methylene group).$2.$ In $(IV)$ $CH_3CHO$ (acetaldehyde) and $(II)$ $CH_3COCH_3$ (acetone),the $\alpha$-hydrogens are acidic due to resonance with one carbonyl group. Aldehydes are more acidic than ketones because the additional methyl group in ketones has an electron-donating $+I$ effect,which destabilizes the carbanion.$3.$ In $(III)$ $CH \equiv CH$ (acetylene),the hydrogen is attached to an $sp$ hybridized carbon,making it acidic,but it is significantly less acidic than the $\alpha$-hydrogens of carbonyl compounds.Therefore,the decreasing order of acidity is: $I > IV > II > III$.

Arrange the acidity of the given four compounds in decreasing order:
$(I)$ $CH_3COCH_2COCH_3$
$(II)$ $CH_3COCH_3$
$(III)$ $CH \equiv CH$
$(IV)$ $CH_3CHO$
Select the correct answer from the codes given below:

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Arrange the acidity of the given four compounds in decreasing order:$(I)$ $CH_3COCH_2COCH_3$$(II)$ $CH_3COCH_3$$(III)$ $CH \equiv CH$$(IV)$ $CH_3CHO$Select the correct answer from the codes given below: