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(C) The $pK_a$ value is inversely proportional to the acidic strength of the compound.Acidic strength order:$IV$ ($p$-Nitrobenzoic acid) > $II$ ($p$-N

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$IV < II < I < III$

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(C) The $pK_a$ value is inversely proportional to the acidic strength of the compound.Acidic strength order:$IV$ ($p$-Nitrobenzoic acid) > $II$ ($p$-Nitrophenol) > $I$ (Phenol) > $III$ (Ethanol).$p$-Nitrobenzoic acid is a carboxylic acid,which is significantly more acidic than phenols and alcohols.$p$-Nitrophenol is more acidic than phenol due to the electron-withdrawing effect of the $-NO_2$ group.Phenol is more acidic than ethanol due to the resonance stabilization of the phenoxide ion.Therefore,the increasing order of $pK_a$ values is the reverse of the acidic strength order:$IV < II < I < III$.

Column-$I$ (Reactant)	Column-$II$ (Product)
$A$. $RCH_2OH \xrightarrow[(ii) H_3O^{+}]{(i) NaOH, KMnO_4} ?$	$i$. $C_6H_5COOH + C_2H_5OH$
$B$. $CH_3(CH_2)_8CH_2OH \xrightarrow{Jones reagent} ?$	$ii$. $RCOOH$
$C$. $RCONH_2 \xrightarrow{H_3O^{+}, \Delta} ?$	$iii$. $CH_3(CH_2)_8COOH$
$D$. $C_6H_5COOEt \xrightarrow{H_3O^{+}} ?$	$iv$. $RCOOH + NH_3$

Arrange the following compounds in the increasing order of their $pK_a$ values:
$I.$ Phenol
$II.$ $p$-Nitrophenol
$III.$ Ethanol
$IV.$ $p$-Nitrobenzoic acid

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Arrange the following compounds in the increasing order of their $pK_a$ values:$I.$ Phenol$II.$ $p$-Nitrophenol$III.$ Ethanol$IV.$ $p$-Nitrobenzoic acid