The following transformation can be carried out in three steps. The reagents required for these three steps in their correct order are:

  • A
    $i$. $NaBH_4$; $ii$. $PCl_5$; $iii$. anhyd. $AlCl_3$
  • B
    $i$. $SOCl_2$; $ii$. anhyd. $AlCl_3$; $iii$. $Zn(Hg)/HCl$
  • C
    $i$. $Zn(Hg)/HCl$; $ii$. $SOCl_2$; $iii$. anhyd. $AlCl_3$
  • D
    $i$. conc. $H_2SO_4$; $ii$. $H_2N-NH_2 \cdot H_2O$; $iii$. $KOH$,ethylene glycol,$\Delta$

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Identify the final product $(D)$ in the following reaction sequence:
Phthalic anhydride $\xrightarrow{PCl_5} (A)$ $\xrightarrow{LiAlH_4} (B)$ $\xrightarrow{PCC} (C)$ $\xrightarrow{HO^-, \Delta} (D)$

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Compound $A$ was treated with a large excess of $CH_3MgBr$. The resulting product was exposed to $POCl_3$ /pyridine to give compound $B$,as one of many products.
Which of the following compounds can be $A$ ?

The acidity of compounds $I-IV$ in water follows the order:
$I.$ ethanol
$II.$ acetic acid
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In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
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In the reaction $Ph-COOH + NaHC^*O_3 \to \text{Product}$,the labeled carbon $C^*$ is found in which of the following products?

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