Arrange the following in order of increasing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $(i)$ $[Fe(CN)_6]^{3-}$: $Fe$ is in $+3$ oxidation state $(3d^5)$. $CN^-$ is a strong-field ligand,causing pairing. Unpaired electrons = $1$.$(ii)

Vedclass · Accepted Answer

$iv, i, ii, iii$

Vedclass · Answer

(C) $(i)$ $[Fe(CN)_6]^{3-}$: $Fe$ is in $+3$ oxidation state $(3d^5)$. $CN^-$ is a strong-field ligand,causing pairing. Unpaired electrons = $1$.$(ii)$ $[MnCl_6]^{3-}$: $Mn$ is in $+3$ oxidation state $(3d^4)$. $Cl^-$ is a weak-field ligand. Unpaired electrons = $4$.$(iii)$ $[FeF_6]^{3-}$: $Fe$ is in $+3$ oxidation state $(3d^5)$. $F^-$ is a weak-field ligand. Unpaired electrons = $5$.$(iv)$ $[Co(NH_3)_6]^{3+}$: $Co$ is in $+3$ oxidation state $(3d^6)$. $NH_3$ is a strong-field ligand,causing pairing. Unpaired electrons = $0$.Increasing order of unpaired electrons: $(iv) < (i) < (ii) < (iii)$.

List-$I$ (Complex)	List-$II$ (Spin only magnetic moment in $B$.$M$.)
$A$. $[Cr(NH_3)_6]^{3+}$	$I$. $4.90$
$B$. $[NiCl_4]^{2-}$	$II$. $3.87$
$C$. $[CoF_6]^{3-}$	$III$. $0.0$
$D$. $[Ni(CN)_4]^{2-}$	$IV$. $2.83$

Arrange the following in order of increasing number of unpaired electrons in them:
$i$. $[Fe(CN)_6]^{3-}$
$ii$. $[MnCl_6]^{3-}$
$iii$. $[FeF_6]^{3-}$
$iv$. $[Co(NH_3)_6]^{3+}$

Similar Questions

The type of isomerism which exists between $[Pd(C_6H_5)_2(SCN)_2]$ and $[Pd(C_6H_5)_2(NCS)_2]$ is

Which method can be used to distinguish $[Co(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_6][Co(NO_2)_6]$?

Which of the following aquated metal ions has the highest paramagnetism?

The total number of possible isomers for square planar $[Pt(Cl)(NO_2)(NO_3)(SCN)]^{2-}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following in order of increasing number of unpaired electrons in them:$i$. $[Fe(CN)_6]^{3-}$$ii$. $[MnCl_6]^{3-}$$iii$. $[FeF_6]^{3-}$$iv$. $[Co(NH_3)_6]^{3+}$