Which method can be used to distinguish [Co(N | vedclass

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(D) These two compounds are coordination isomers. In the first complex,$[Co(NH_3)_6][Cr(NO_2)_6]$,the cation is $[Co(NH_3)_6]^{3+}$ and the anion is $

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by electrolysis of their aqueous solutions

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(D) These two compounds are coordination isomers. In the first complex,$[Co(NH_3)_6][Cr(NO_2)_6]$,the cation is $[Co(NH_3)_6]^{3+}$ and the anion is $[Cr(NO_2)_6]^{3-}$. In the second complex,$[Cr(NH_3)_6][Co(NO_2)_6]$,the cation is $[Cr(NH_3)_6]^{3+}$ and the anion is $[Co(NO_2)_6]^{3-}$. Upon electrolysis of their aqueous solutions,the metal ions present in the cationic complex will migrate to the cathode and be deposited. For $[Co(NH_3)_6][Cr(NO_2)_6]$,$Co$ metal is deposited at the cathode. For $[Cr(NH_3)_6][Co(NO_2)_6]$,$Cr$ metal is deposited at the cathode. Thus,they can be distinguished by the electrolysis of their aqueous solutions.

Which method can be used to distinguish $[Co(NH_3)_6][Cr(NO_2)_6]$ and $[Cr(NH_3)_6][Co(NO_2)_6]$?

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