Arrange the following species in the decreasi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The bond order $(BO)$ is calculated using the formula: $BO = \frac{N_b - N_a}{2}$,where $N_b$ is the number of electrons in bonding molecular orbi

Vedclass · Accepted Answer

$II > I > III$

Vedclass · Answer

(B) The bond order $(BO)$ is calculated using the formula: $BO = \frac{N_b - N_a}{2}$,where $N_b$ is the number of electrons in bonding molecular orbitals and $N_a$ is the number of electrons in antibonding molecular orbitals.For $NO^+$ ($14$ electrons): The configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2$. $BO = \frac{10 - 4}{2} = 3.0$.For $NO$ ($15$ electrons): The configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$. $BO = \frac{10 - 5}{2} = 2.5$.For $NO^-$ ($16$ electrons): The configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1 = \pi^* 2p_y^1$. $BO = \frac{10 - 6}{2} = 2.0$.Comparing the bond orders: $3.0 (II) > 2.5 (I) > 2.0 (III)$.Thus,the decreasing order is $II > I > III$.

Arrange the following species in the decreasing order of their bond orders:
$(I)$ $NO$
$(II)$ $NO^+$
$(III)$ $NO^-$

Similar Questions

Which of the following statements is incorrect when $C_2$ changes to $C_2^{2-}$?

Which of the following species is paramagnetic?

The difference between bond orders of $CO$ and $NO^{\oplus}$ is $\frac{x}{2}$ where $x = .....$
(Round off to the Nearest Integer)

What is the number of electrons in bonding molecular orbitals and antibonding molecular orbitals respectively in $F_2$ molecule?

Two $\pi$ and half $\sigma$ bonds are present in

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Arrange the following species in the decreasing order of their bond orders:$(I)$ $NO$$(II)$ $NO^+$$(III)$ $NO^-$