Arrange the stability of the given gem-diols | vedclass

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(A) The stability of gem-diols is governed by the bond angles within the ring. In small rings,the internal bond angle is constrained (e.g.,$60^{\circ}

Vedclass · Accepted Answer

$III > II > I$

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(A) The stability of gem-diols is governed by the bond angles within the ring. In small rings,the internal bond angle is constrained (e.g.,$60^{\circ}$ in cyclopropane,$90^{\circ}$ in cyclobutane).When two hydroxyl $(-OH)$ groups are attached to the same carbon,there is significant steric repulsion between them. This repulsion is minimized when the bond angle between the two $-OH$ groups is larger.As the ring size increases from cyclopropane $(I)$ to cyclobutane $(II)$ to cyclopentane $(III)$,the internal bond angle increases,which allows the $-OH$ groups to move further apart,reducing steric hindrance and increasing stability.Therefore,the stability order is $III > II > I$.

Arrange the stability of the given gem-diols in decreasing order:
$I$: Cyclopropane$-1,1-$diol
$II$: Cyclobutane$-1,1-$diol
$III$: Cyclopentane$-1,1-$diol

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Arrange the stability of the given gem-diols in decreasing order:$I$: Cyclopropane$-1,1-$diol$II$: Cyclobutane$-1,1-$diol$III$: Cyclopentane$-1,1-$diol