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(C) The side length of the square plot $ABCD$ is $l = 50 \, m$.Area of the square plot $ABCD = l^2 = 50 	imes 50 = 2500 \, m^2$.For the flower beds f

Vedclass · Accepted Answer

$2186$

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(C) The side length of the square plot $ABCD$ is $l = 50 \, m$.Area of the square plot $ABCD = l^2 = 50 	imes 50 = 2500 \, m^2$.For the flower beds formed at each vertex,the radius is $r = 10 \, m$ and the angle of the sector is $	heta = 90^\circ$ (since it is a square).Area of one flower bed (sector) $= \frac{	heta}{360^\circ} 	imes \pi r^2 = \frac{90^\circ}{360^\circ} 	imes 3.14 	imes 10^2 = \frac{1}{4} 	imes 3.14 	imes 100 = 78.5 \, m^2$.Total area of $4$ flower beds $= 4 	imes 78.5 = 314 \, m^2$.Area of the plot excluding the flower beds $=$ Area of the square plot $-$ Total area of the flower beds.$= 2500 - 314 = 2186 \, m^2$.Thus,the area of the plot excluding the flower beds is $2186 \, m^2$.

As shown in the adjoining diagram,the length of the side of the square plot $ABCD$ is $50 \, m$. At each vertex of the plot,a flower bed in the shape of a sector with radius $10 \, m$ is prepared. Find the area of the plot excluding the flower beds. $(\pi = 3.14)$ (in $m^2$)

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