The radius of a circle is 3.5,cm. The area of | vedclass

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(B) Given,the radius of the circle $r = 3.5\,cm = \frac{7}{2}\,cm$.Since the two radii are perpendicular,the central angle $	heta = 90^\circ$.The are

Vedclass · Accepted Answer

$9.625$

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(B) Given,the radius of the circle $r = 3.5\,cm = \frac{7}{2}\,cm$.Since the two radii are perpendicular,the central angle $	heta = 90^\circ$.The area of a minor sector is given by the formula:Area $= \frac{	heta}{360^\circ} 	imes \pi r^2$Area $= \frac{90^\circ}{360^\circ} 	imes \frac{22}{7} 	imes (3.5)^2$Area $= \frac{1}{4} 	imes \frac{22}{7} 	imes 3.5 	imes 3.5$Area $= \frac{1}{4} 	imes 22 	imes 0.5 	imes 3.5$Area $= \frac{1}{4} 	imes 38.5 = 9.625\,cm^2$.

The radius of a circle is $3.5\,cm$. The area of the minor sector formed by two perpendicular radii of that circle is $\ldots \ldots \ldots \,cm^2$.

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