As shown in the figure,a metal rod makes cont | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given: Magnetic field $B = 0.15 \, T$,velocity $v = 2 \, m/s$,resistance $R = 3 \, \Omega$,and length of the rod $l = 50 \, cm = 0.5 \, m$.The ind

Vedclass · Accepted Answer

$3.75 	imes 10^{-3} \, N$

Vedclass · Answer

(A) Given: Magnetic field $B = 0.15 \, T$,velocity $v = 2 \, m/s$,resistance $R = 3 \, \Omega$,and length of the rod $l = 50 \, cm = 0.5 \, m$.The induced electromotive force $(EMF)$ in the rod is given by $\varepsilon = Bvl$.The induced current in the circuit is $i = \frac{\varepsilon}{R} = \frac{Bvl}{R}$.The magnetic force acting on the current-carrying rod is $F_m = Bil$.Substituting the value of $i$,we get $F_m = B \left( \frac{Bvl}{R} ight) l = \frac{B^2 v l^2}{R}$.To move the rod with a constant speed,the external force $F_{ext}$ must be equal and opposite to the magnetic force $F_m$.$F_{ext} = F_m = \frac{B^2 v l^2}{R} = \frac{(0.15)^2 	imes 2 	imes (0.5)^2}{3}$.$F_{ext} = \frac{0.0225 	imes 2 	imes 0.25}{3} = \frac{0.01125}{3} = 0.00375 \, N = 3.75 	imes 10^{-3} \, N$.

As shown in the figure,a metal rod makes contact and completes the circuit. The circuit is perpendicular to the magnetic field with $B = 0.15 \, T$. If the resistance is $3 \, \Omega$,the force needed to move the rod as indicated with a constant speed of $2 \, m/s$ is:

Similar Questions

$A$ thin rectangular magnet suspended freely has a period of oscillation equal to $T.$ Now it is broken into two equal halves (each having half of the original length) and one piece is made to oscillate freely in the same field. If its period of oscillation is $T',$ the ratio $T'/T$ is :-

Which carbohydrate is used in the silvering of mirrors?

In the measurement of a physical quantity $X = \frac{A^2 B}{C^{1/3} D^3}$,the percentage errors in the measurements of $A, B, C$,and $D$ are $2\%, 2\%, 4\%$,and $5\%$,respectively. The minimum percentage error in the measurement of $X$ is contributed by:

Three perfect gases at absolute temperatures $T_1, T_2$ and $T_3$ are mixed. The masses of molecules are $m_1, m_2$ and $m_3$ and the number of molecules are $n_1, n_2$ and $n_3$ respectively. Assuming no loss of energy,the final temperature of the mixture is

If $3 \cos x \neq 2 \sin x$,then the general solution of $\sin^2 x - \cos 2x = 2 - \sin 2x$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module