Assertion: Four point charges q_1, q_2, q_3 a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\epsilon_0}$.In th

Vedclass · Accepted Answer

If Assertion is correct but Reason is incorrect.

Vedclass · Answer

(C) According to Gauss's Law,the total electric flux $\phi$ through a closed surface is given by $\phi = \frac{q_{	ext{enclosed}}}{\epsilon_0}$.In the given figure,the charges enclosed by the Gaussian surface are $q_1$ and $q_2$. Therefore,the flux depends only on $q_1$ and $q_2$. Thus,the Assertion is correct.However,the electric field at any point on the Gaussian surface is the vector sum of the electric fields produced by all the charges present in the space ($q_1, q_2, q_3$ and $q_4$). Therefore,the electric field at any point on the surface depends on all the charges,not just the enclosed ones. Thus,the Reason is incorrect.

Assertion: Four point charges $q_1, q_2, q_3$ and $q_4$ are as shown in the figure. The flux over the shown Gaussian surface depends only on charges $q_1$ and $q_2$.
Reason: Electric field at all points on the Gaussian surface depends only on charges $q_1$ and $q_2$.

Similar Questions

Identify the $WRONG$ statement in the case of electric field lines.

$A$ metallic solid sphere is placed in a uniform electric field. The lines of force follow the path$(s)$ shown in the figure as:

$A$ point charge '$q$' coulomb is placed at the centre of a cube of side length '$L$'. Then the electric flux linked with each face of the cube is

$A$ circular plate sheet of radius $10 \,cm$ is placed in a uniform electric field of $2 \sqrt{3} \times 10^5 \,NC^{-1}$, making an angle of $60^{\circ}$ with the field. Find the electric flux through the sheet.

Gauss's law states that

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion: Four point charges $q_1, q_2, q_3$ and $q_4$ are as shown in the figure. The flux over the shown Gaussian surface depends only on charges $q_1$ and $q_2$.Reason: Electric field at all points on the Gaussian surface depends only on charges $q_1$ and $q_2$.