Assertion A: Hydrolysis of an alkyl chloride | vedclass

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(C) The hydrolysis of alkyl chloride $(R-Cl)$ is slow because $Cl^-$ is a poor nucleophile.When $NaI$ is added,$I^-$ acts as a strong nucleophile and

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Both $A$ and $R$ are true and $R$ is the correct explanation of $A$

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(C) The hydrolysis of alkyl chloride $(R-Cl)$ is slow because $Cl^-$ is a poor nucleophile.When $NaI$ is added,$I^-$ acts as a strong nucleophile and attacks the alkyl chloride to form an alkyl iodide $(R-I)$ via an $S_N2$ reaction.Since $I^-$ is a much better leaving group than $Cl^-$,the subsequent hydrolysis of $R-I$ to form the alcohol $(R-OH)$ occurs much faster.Thus,$I^-$ acts as a catalyst by converting the alkyl chloride into a more reactive alkyl iodide.Both $A$ and $R$ are true,and $R$ is the correct explanation of $A$.

Assertion $A:$ Hydrolysis of an alkyl chloride is a slow reaction but in the presence of $NaI$,the rate of the hydrolysis increases.
Reason $R:$ $I^{-}$ is a good nucleophile as well as a good leaving group.
In the light of the above statements,choose the correct answer from the options given below.

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What would be the effect of increasing solvent polarity on the rate of each of the following reactions? ($Nu =$ neutral nucleophile)
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Pure $CHCl_3$ and pure $CHI_3$ can be distinguished by which of the following?

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Assertion $A:$ Hydrolysis of an alkyl chloride is a slow reaction but in the presence of $NaI$,the rate of the hydrolysis increases.Reason $R:$ $I^{-}$ is a good nucleophile as well as a good leaving group.In the light of the above statements,choose the correct answer from the options given below.