Assertion (A): If A=10^{circ}, B=16^{circ}, C | vedclass

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(A) Given $A=10^{\circ}, B=16^{\circ}, C=19^{\circ}$.Then $2A=20^{\circ}, 2B=32^{\circ}, 2C=38^{\circ}$.Sum $2A+2B+2C = 20^{\circ}+32^{\circ}+38^{\cir

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Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$

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(A) Given $A=10^{\circ}, B=16^{\circ}, C=19^{\circ}$.Then $2A=20^{\circ}, 2B=32^{\circ}, 2C=38^{\circ}$.Sum $2A+2B+2C = 20^{\circ}+32^{\circ}+38^{\circ} = 90^{\circ}$.For any three angles $X, Y, Z$ such that $X+Y+Z=90^{\circ}$,we have $	an X 	an Y + 	an Y 	an Z + 	an Z 	an X = 1$.Substituting $X=2A, Y=2B, Z=2C$,we get $	an 2A 	an 2B + 	an 2B 	an 2C + 	an 2C 	an 2A = 1$.Thus,Assertion $(A)$ is true.The Reason $(R)$ states the general identity: if $X+Y+Z=90^{\circ}$,then $	an X 	an Y + 	an Y 	an Z + 	an Z 	an X = 1$.This is the correct mathematical principle used to prove the Assertion.Therefore,both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$.

Assertion $(A)$: If $A=10^{\circ}, B=16^{\circ}, C=19^{\circ}$,then $\tan 2A \tan 2B + \tan 2B \tan 2C + \tan 2C \tan 2A = 1$.
Reason $(R)$: If $A+B+C=90^{\circ}$,then $\tan A \tan B + \tan B \tan C + \tan C \tan A = 1$.
Which of the following is correct?

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Assertion $(A)$: If $A=10^{\circ}, B=16^{\circ}, C=19^{\circ}$,then $\tan 2A \tan 2B + \tan 2B \tan 2C + \tan 2C \tan 2A = 1$.Reason $(R)$: If $A+B+C=90^{\circ}$,then $\tan A \tan B + \tan B \tan C + \tan C \tan A = 1$.Which of the following is correct?