(B) The reaction $FeS \downarrow + 2HCl \longrightarrow FeCl_2 + H_2S \uparrow$ involves the solid iron$(II)$ sulfide $(FeS)$ reacting with hydrochlor

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For precipitate dissolution reaction

(B) The reaction $FeS \downarrow + 2HCl \longrightarrow FeCl_2 + H_2S \uparrow$ involves the solid iron$(II)$ sulfide $(FeS)$ reacting with hydrochloric acid $(HCl)$ to form soluble iron$(II)$ chloride $(FeCl_2)$ and hydrogen sulfide gas $(H_2S)$.Since $FeS$ is a solid precipitate that dissolves upon reacting with the acid,this is classified as a precipitate dissolution reaction.Therefore,the correct option is $B$.

Class 11 Chemistry 2 Equilibrium: Ionic Equilibrium Solubility product

Medium

Assign $A, B, C, D$ from the given type of reaction.
$FeS \downarrow + 2HCl \longrightarrow FeCl_2 + H_2S \uparrow$

A
For precipitate formation reaction
B
For precipitate dissolution reaction
C
For precipitate exchange reaction
D
For no reaction

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2 Equilibrium: Ionic Equilibrium

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Solubility product

What is the concentration of $Ba^{2+}$ when $BaF_2$ $(K_{sp} = 1.0 \times 10^{-6})$ begins to precipitate from a solution that is $0.30 \, M \ F^{-}$?

Medium

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Solubility of an $MX_2$ type electrolyte is $0.5 \times 10^{-4} \ mol/L$,then $K_{sp}$ of electrolyte is

Medium

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Assertion : $BaCO_3$ is more soluble in $HNO_3$ than in plain water.
Reason : Carbonate is a weak base and reacts with the $H^+$ from the strong acid,causing the barium salt to dissociate.

DifficultAIIMS 2003

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The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.

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Explain the equilibrium involving the dissolution of a solid in a liquid.

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Assign $A, B, C, D$ from the given type of reaction.$FeS \downarrow + 2HCl \longrightarrow FeCl_2 + H_2S \uparrow$

Similar Questions

What is the concentration of $Ba^{2+}$ when $BaF_2$ $(K_{sp} = 1.0 \times 10^{-6})$ begins to precipitate from a solution that is $0.30 \, M \ F^{-}$?

Solubility of an $MX_2$ type electrolyte is $0.5 \times 10^{-4} \ mol/L$,then $K_{sp}$ of electrolyte is

Assertion : $BaCO_3$ is more soluble in $HNO_3$ than in plain water.Reason : Carbonate is a weak base and reacts with the $H^+$ from the strong acid,causing the barium salt to dissociate.

The solubility of calcium carbonate $(CaCO_3)$ at $298 \ K$ is $6.4 \times 10^{-5} \ mol \ dm^{-3}$. Calculate the value of solubility product $(K_{sp})$ at the same temperature.

Explain the equilibrium involving the dissolution of a solid in a liquid.

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Assign $A, B, C, D$ from the given type of reaction.
$FeS \downarrow + 2HCl \longrightarrow FeCl_2 + H_2S \uparrow$

Assertion : $BaCO_3$ is more soluble in $HNO_3$ than in plain water.
Reason : Carbonate is a weak base and reacts with the $H^+$ from the strong acid,causing the barium salt to dissociate.