Assume that a block of very low shear modulus | vedclass

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(A) The block is fixed to an inclined plane. Gravity acts on the block,which can be resolved into two components: one perpendicular to the inclined pl

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(A) The block is fixed to an inclined plane. Gravity acts on the block,which can be resolved into two components: one perpendicular to the inclined plane $(mg \cos 	heta)$ and one parallel to the inclined plane $(mg \sin 	heta)$.The component $mg \sin 	heta$ acts as a shear force on the block,causing it to deform due to its low shear modulus. This deformation is a shear strain,which results in the block tilting in the direction of the force.Since the base is fixed,the top surface of the block will shift parallel to the inclined plane while the vertical sides will tilt. This results in the block taking the shape of a parallelogram,as shown in option $A$.

Assume that a block of very low shear modulus is fixed on an inclined plane as shown. Due to elastic forces,it will deform. What will be the shape of the block?

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