Assuming an ideal diode,find the current thro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the given circuit,the top branch contains a diode in forward bias,and the middle branch contains a Zener diode in reverse bias (as the cathode

Vedclass · Accepted Answer

$2 \ A$

Vedclass · Answer

(A) In the given circuit,the top branch contains a diode in forward bias,and the middle branch contains a Zener diode in reverse bias (as the cathode is connected to the positive terminal of the battery). $1$. The diode in the top branch is in forward bias,so it acts as a short circuit (ideal diode). The resistance in this branch is $2 \Omega$. $2$. The Zener diode in the middle branch is in reverse bias,so it acts as an open circuit. No current flows through this branch. $3$. The total resistance of the circuit is the resistance of the top branch $(2 \Omega)$ in parallel with the middle branch (open circuit,so infinite resistance),which is $2 \Omega$. This is then in series with the $1 \Omega$ internal resistance. $4$. Total resistance $R_{eq} = 2 \Omega + 1 \Omega = 3 \Omega$. $5$. The current through the $1 \Omega$ resistor is the total current supplied by the $6 \ V$ battery: $I = \frac{V}{R_{eq}} = \frac{6 \ V}{3 \Omega} = 2 \ A$.

Assuming an ideal diode,find the current through the $1 \Omega$ resistance in the circuit shown in the figure.

Similar Questions

For the diagram shown,the resistance between points $A$ and $B$ when the ideal diode '$D$' is forward biased is '$R_1$' and that when reverse biased is '$R_2$'. The ratio $\frac{R_1}{R_2}$ is

The depletion layer in a silicon diode is $1 \, \mu m$ wide and the knee potential is $0.6 \, V$. The electric field in the depletion layer is:

Find the value of $V_{AB}$ in the given circuit.

What is breakdown voltage and saturation current?

Vedclass Test Series

Exam Paper Generator

Online Exam Module