At 400 K temperature in a closed vessel,the | vedclass

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(A) According to Dalton's law of partial pressures,the partial pressure of a gas is equal to its mole fraction multiplied by the total pressure.  Sinc

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$p_{He} = 10 \ bar, p_{Ne} = 10 \ bar, p_{Ar} = 5 \ bar$

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(A) According to Dalton's law of partial pressures,the partial pressure of a gas is equal to its mole fraction multiplied by the total pressure.  Since the volume percentage is equal to the mole fraction for ideal gases,we have:  $p_{He} = \chi_{He} 	imes P_{total} = 0.40 	imes 25 \ bar = 10 \ bar$  $p_{Ne} = \chi_{Ne} 	imes P_{total} = 0.40 	imes 25 \ bar = 10 \ bar$  $p_{Ar} = \chi_{Ar} 	imes P_{total} = 0.20 	imes 25 \ bar = 5 \ bar$

At $400 \ K$ temperature in a closed vessel,the $\%$ by volume of $He, Ne$,and $Ar$ are $40\%, 40\%$,and $20\%$ respectively. If the total pressure is $25 \ bar$,find the partial pressure of each gas.

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