At T text{ K},the ratio of kinetic energies o | vedclass

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(D) The kinetic energy $(KE)$ of $n$ moles of an ideal gas at temperature $T$ is given by $KE = n 	imes \frac{3}{2} RT$. For $4 	ext{ g}$ of $H_2$:

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$8: 1$

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(D) The kinetic energy $(KE)$ of $n$ moles of an ideal gas at temperature $T$ is given by $KE = n 	imes \frac{3}{2} RT$. For $4 	ext{ g}$ of $H_2$: Moles $n_1 = \frac{4 	ext{ g}}{2 	ext{ g/mol}} = 2 	ext{ mol}$. $KE_{H_2} = 2 	imes \frac{3}{2} RT = 3RT$. For $8 	ext{ g}$ of $O_2$: Moles $n_2 = \frac{8 	ext{ g}}{32 	ext{ g/mol}} = 0.25 	ext{ mol} = \frac{1}{4} 	ext{ mol}$. $KE_{O_2} = \frac{1}{4} 	imes \frac{3}{2} RT = \frac{3}{8} RT$. Ratio $KE_{H_2} : KE_{O_2} = 3RT : \frac{3}{8} RT = 1 : \frac{1}{8} = 8 : 1$.

At $T \text{ K}$,the ratio of kinetic energies of $4 \text{ g}$ of $H_{2(g)}$ and $8 \text{ g}$ of $O_{2(g)}$ is

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