At 25^{circ} C, the ionic product of water is | vedclass

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(C) The self-ionization reaction of water is: $H_2O(\ell) \rightleftharpoons H^{+}_{(aq)} + OH^{-}_{(aq)}$ with $K_w = 10^{-14}$.The standard Gibbs fr

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$19.1$

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(C) The self-ionization reaction of water is: $H_2O(\ell) ightleftharpoons H^{+}_{(aq)} + OH^{-}_{(aq)}$ with $K_w = 10^{-14}$.The standard Gibbs free energy change is given by: $\Delta G^{\circ} = -RT \ln K_w = -2.303 RT \log K_w$.Given $R = 1.987 	imes 10^{-3} \ kCal \ K^{-1} \ mol^{-1}$ and $T = 298 \ K$:$\Delta G^{\circ} = -2.303 	imes (1.987 	imes 10^{-3}) 	imes 298 	imes \log(10^{-14})$$\Delta G^{\circ} = -2.303 	imes 1.987 	imes 10^{-3} 	imes 298 	imes (-14)$$\Delta G^{\circ} \approx 19.1 \ kCal \ mol^{-1}$.

At $25^{\circ} C$, the ionic product of water is $10^{-14}$. The free energy change for the self-ionization of water in $kCal \ mol^{-1}$ is close to

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