Bag $I$ contains $3$ red and $2$ green balls and Bag $II$ contains $5$ red and $3$ green balls. $A$ ball is drawn from one of the bags at random and it is found to be green. Then the probability that it is drawn from Bag $I$ is

  • A
    $\frac{8}{31}$
  • B
    $\frac{12}{31}$
  • C
    $\frac{14}{31}$
  • D
    $\frac{16}{31}$

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