Balls A and B are thrown from two points lyin | vedclass

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(C) For the balls to meet,they must have the same horizontal position and the same vertical position at the same time $t$.Let the horizontal velocity

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The two balls meet at a height of $45\,m$

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(C) For the balls to meet,they must have the same horizontal position and the same vertical position at the same time $t$.Let the horizontal velocity of ball $A$ be $v_{Ax} = 50 \cos 37^{\circ} = 50 	imes (4/5) = 40\,m/s$.Let the horizontal velocity of ball $B$ be $v_{Bx} = 0\,m/s$ (since it is thrown vertically).For the balls to meet,ball $A$ must travel the horizontal distance of $120\,m$ to reach the vertical line of ball $B$.Time taken by ball $A$ to reach the vertical line of $B$ is $t = \frac{120\,m}{40\,m/s} = 3\,s$.Now,check the vertical heights of both balls at $t = 3\,s$:For ball $A$: $v_{Ay} = 50 \sin 37^{\circ} = 50 	imes (3/5) = 30\,m/s$.$h_A = v_{Ay} t - \frac{1}{2} g t^2 = 30(3) - \frac{1}{2}(10)(3)^2 = 90 - 45 = 45\,m$.For ball $B$: $v_{By} = 30\,m/s$.$h_B = v_{By} t - \frac{1}{2} g t^2 = 30(3) - \frac{1}{2}(10)(3)^2 = 90 - 45 = 45\,m$.Since $h_A = h_B$ at $t = 3\,s$,the balls meet at a height of $45\,m$ if thrown simultaneously.

Balls $A$ and $B$ are thrown from two points lying on the same horizontal plane separated by a distance of $120\,m$. Which of the following statement$(s)$ is/are correct?

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