Benzaldehyde on heating with concentrated $NaOH$ gives:

An organic compound $(A)$ with molecular formula $C_8H_8O$ forms an orange-red precipitate with $2,4-DNP$ reagent and gives a yellow precipitate on heating with iodine in the presence of sodium hydroxide. It neither reduces Tollens' or Fehlings' reagent,nor does it decolourise bromine water or Baeyer's reagent. On drastic oxidation with chromic acid,it gives a carboxylic acid $(B)$ having molecular formula $C_7H_6O_2$. Identify the compounds $(A)$ and $(B)$ and explain the reactions involved.

Which of the following compounds will give a silver mirror test with ammoniacal silver nitrate (Tollens' reagent)?
$(A)$ Formic acid
$(B)$ Formaldehyde
$(C)$ Benzaldehyde
$(D)$ Acetone
Choose the correct answer from the options given below:

How can $A$ and $B$ be differentiated?

The reagent used in the Wolff-Kishner reduction is:

The major product $(Y)$ in the following reactions is
$CH_3-CH(CH_3)-C\equiv CH$ $\xrightarrow[H_2O]{HgSO_4, H_2SO_4} X$ $\xrightarrow[(ii) \ conc. H_2SO_4 / \Delta]{(i) \ C_2H_5MgBr, H_2O} Y$