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(C) The average speed is defined as the total distance traveled divided by the total time taken.Total distance = Area under the $v-t$ graph.The $v-t$

Vedclass · Accepted Answer

$54$

Vedclass · Answer

(C) The average speed is defined as the total distance traveled divided by the total time taken.Total distance = Area under the $v-t$ graph.The $v-t$ graph is a trapezium with parallel sides of length $8t$ and $(t + 8t + t) = 10t$,and height $v_{max} = 60\,km/h$.Total distance = $\frac{1}{2} 	imes (8t + 10t) 	imes 60 = \frac{1}{2} 	imes 18t 	imes 60 = 540t$.Total time = $t + 8t + t = 10t$.Average speed = $\frac{	ext{Total distance}}{	ext{Total time}} = \frac{540t}{10t} = 54\,km/h$.

Between two stations,a train accelerates uniformly at first,then moves with constant velocity,and finally retards uniformly. If the ratio of the time taken is $1 : 8 : 1$ and the maximum speed attained is $60\,km/h,$ what is the average speed over the whole journey in $km/h$?

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