Boron forms BX_3 type of halides. The correct | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Lewis acidity of boron halides depends on the extent of $p\pi-p\pi$ back-bonding between the halogen atom and the boron atom.The tendency for

Vedclass · Accepted Answer

$BI_3 > BBr_3 > BCl_3 > BF_3$

Vedclass · Answer

(B) The Lewis acidity of boron halides depends on the extent of $p\pi-p\pi$ back-bonding between the halogen atom and the boron atom.The tendency for back-donation from the halogen to the vacant $p$-orbital of boron is highest in $BF_3$ due to the small size of the fluorine atom,which allows for effective overlap.As the size of the halogen increases from $F$ to $I$,the effectiveness of back-bonding decreases,making the boron atom more electron-deficient.Therefore,the decreasing order of Lewis acidity is $BI_3 > BBr_3 > BCl_3 > BF_3$.

Column-$1$ (Reaction)	Column-$2$ (Main product)
$A$. $B_2H_6 + 2CO \longrightarrow$	$I$. $B_2O_3$
$B$. $B_2H_6 + 3O_2 \longrightarrow$	$II$. $2BH_3 \cdot CO$
$C$. $B_2H_6 + 6H_2O \longrightarrow$	$III$. $2H_3BO_3$

Boron forms $BX_3$ type of halides. The correct increasing order of Lewis-acid strength of these halides is

Similar Questions

The weakest Lewis acid is

Which of the following on hydrolysis produces diborane $(B_2H_6)$?

Which of the following statements is correct?

Which of the following is the least basic?

Vedclass Test Series

Exam Paper Generator

Online Exam Module