Bulk modulus of water is 2 times 10^9 N/m^2. | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetri

Vedclass · Accepted Answer

$2 	imes 10^6$

Vedclass · Answer

(C) The formula for Bulk modulus $(K)$ is given by $K = -\frac{p}{\Delta V / V}$,where $p$ is the change in pressure and $\Delta V/V$ is the volumetric strain.Since we are increasing the volume,the pressure change $p$ acts as a negative pressure (tensile stress).Given: $K = 2 	imes 10^9 \ N/m^2$ and $\frac{\Delta V}{V} = 0.1 \% = 0.1 / 100 = 10^{-3}$.Substituting the values into the formula: $2 	imes 10^9 = \frac{p}{10^{-3}}$.Therefore,$p = 2 	imes 10^9 	imes 10^{-3} = 2 	imes 10^6 \ N/m^2$.

Bulk modulus of water is $2 \times 10^9 \ N/m^2$. The pressure required to increase the volume of water by $0.1 \%$ in $N/m^2$ is:

Similar Questions

The condition that $f(x)=a x^3+b x^2+c x+d$ has no extreme value,is

Which of the following is not correct regarding the properties of ionic compounds?

Suppose the gravitational force varies inversely as the $n^{th}$ power of distance. Then the time period of a planet in a circular orbit of radius $R$ around the sun will be proportional to

Which of the following properties does not support the anomalous behavior of boron?

Find the value of $V_{AB}$ in the given circuit.

Vedclass Test Series

Exam Paper Generator

Online Exam Module