Find the value of V_{AB} in the given circuit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The diode is in forward bias,so it acts as a short circuit (assuming an ideal diode).The circuit consists of a $10 \ \Omega$ resistor in series wi

Vedclass · Accepted Answer

$10 \ V$

Vedclass · Answer

(A) The diode is in forward bias,so it acts as a short circuit (assuming an ideal diode).The circuit consists of a $10 \ \Omega$ resistor in series with a parallel combination of a $10 \ \Omega$ resistor and another $10 \ \Omega$ resistor.The equivalent resistance of the parallel part is $R_p = \frac{10 	imes 10}{10 + 10} = 5 \ \Omega$.The total resistance of the circuit is $R_{eq} = 10 \ \Omega + 5 \ \Omega = 15 \ \Omega$.The total current in the circuit is $I = \frac{V}{R_{eq}} = \frac{30 \ V}{15 \ \Omega} = 2 \ A$.The voltage $V_{AB}$ is the voltage across the parallel combination,which is $V_{AB} = I 	imes R_p = 2 \ A 	imes 5 \ \Omega = 10 \ V$.

Find the value of $V_{AB}$ in the given circuit.

Similar Questions

Which one of the following is most acidic?

If $x$ is real,then the value of $\frac{x^2-3x+4}{x^2+3x+4}$ lies in the interval

If $\log x : \log y : \log z = (y - z) : (z - x) : (x - y)$,then

$A$ body is rolling down an inclined plane. If the kinetic energy of rotation is $40\%$ of the translational kinetic energy,then the body is a

The set of solutions of the equation $(\sqrt{3}-1) \sin \theta+(\sqrt{3}+1) \cos \theta=2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module