By adding 20 mL of 0.1 N HCl to 20 mL of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Calculate the number of gram equivalents of $HCl$ and $KOH$.$g \ eq. \ of \ HCl = N 	imes V(L) = 0.1 	imes 0.020 = 2 	imes 10^{-3} \

Vedclass · Accepted Answer

$1.3$

Vedclass · Answer

(B) Step $1$: Calculate the number of gram equivalents of $HCl$ and $KOH$.$g \ eq. \ of \ HCl = N 	imes V(L) = 0.1 	imes 0.020 = 2 	imes 10^{-3} \ g \ eq.$$g \ eq. \ of \ KOH = N 	imes V(L) = 0.001 	imes 0.020 = 2 	imes 10^{-5} \ g \ eq.$Step $2$: Calculate the remaining $HCl$ after neutralization.$g \ eq. \ of \ HCl \ 	ext{left} = 2 	imes 10^{-3} - 2 	imes 10^{-5} = 2 	imes 10^{-3} - 0.02 	imes 10^{-3} = 1.98 	imes 10^{-3} \ g \ eq.$Step $3$: Calculate the concentration of $H^+$ ions in the final volume.Total volume $= 20 \ mL + 20 \ mL = 40 \ mL = 0.040 \ L$.$[H^+] = \frac{1.98 	imes 10^{-3} \ g \ eq.}{0.040 \ L} = 4.95 	imes 10^{-2} \ M$.Step $4$: Calculate the $pH$.$pH = -\log[H^+] = -\log(4.95 	imes 10^{-2}) = 2 - \log(4.95) \approx 2 - 0.6946 \approx 1.305$.Thus,the $pH$ is approximately $1.3$.

By adding $20 \ mL$ of $0.1 \ N \ HCl$ to $20 \ mL$ of $0.001 \ N \ KOH$,the $pH$ of the resulting solution will be:

Similar Questions

Calculate the concentration of hydrogen ions $[H^+]$ in the following solutions: $(a)$ $0.001 \ M \ HNO_3$ $(b)$ $0.0001 \ M \ KOH$.

What will be the $pH$ of a solution formed by mixing $40 \, mL$ of $0.10 \, M \, HCl$ with $10 \, mL$ of $0.45 \, M \, NaOH$?

The $pH$ of $1 \ L$ of an aqueous solution of $HCl$ is $1$. How many liters of water must be added to make the $pH$ of this solution $2$ (in $L$)?

The hydrogen ion concentration of a $10^{-8} \ M \ HCl$ aqueous solution at $298 \ K$ $(K_w = 10^{-14})$ is

What will be the resultant $pH$ when $100 \ mL$ of an aqueous solution of $HCl$ $(pH = 2)$ is mixed with $200 \ mL$ of an aqueous solution of $NaOH$ $(pH = 12)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module