By the Remainder Theorem,find the remainder w | vedclass

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(C) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x - 3$,we set $g(x) = 0$ t

Vedclass · Accepted Answer

$62$

Vedclass · Answer

(C) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x - 3$,we set $g(x) = 0$ to find the value of $x$:$x - 3 = 0 \Rightarrow x = 3$.Now,we substitute $x = 3$ into the polynomial $p(x)$:$p(3) = (3)^{3} - 3(3)^{2} + 4(3) + 50$$p(3) = 27 - 3(9) + 12 + 50$$p(3) = 27 - 27 + 12 + 50$$p(3) = 0 + 62 = 62$.Therefore,the remainder is $62$.

By the Remainder Theorem,find the remainder when $p(x)$ is divided by $g(x)$,where $p(x) = x^{3} - 3x^{2} + 4x + 50$ and $g(x) = x - 3$.

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