By the graphical method,find whether the following pair of equations are consistent or not. If consistent,solve them.
$3x + y + 4 = 0$
$6x - 2y + 4 = 0$

(A) The given pair of equations is:
$3x + y + 4 = 0 .....(i)$
$6x - 2y + 4 = 0 .....(ii)$
Comparing with $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:
$a_1 = 3, b_1 = 1, c_1 = 4$
$a_2 = 6, b_2 = -2, c_2 = 4$
Calculating ratios:
$\frac{a_1}{a_2} = \frac{3}{6} = \frac{1}{2}$
$\frac{b_1}{b_2} = \frac{1}{-2} = -\frac{1}{2}$
Since $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$,the lines intersect at a unique point. Therefore,the system is consistent.
For equation $(i)$,$y = -3x - 4$:

$x$	$0$	$-1$	$-2$
$y$	$-4$	$-1$	$2$

For equation $(ii)$,$2y = 6x + 4 \Rightarrow y = 3x + 2$:

$x$	$-1$	$0$	$1$
$y$	$-1$	$2$	$5$

Plotting these lines on a graph,they intersect at the point $(-1, -1)$. Thus,the solution is $x = -1, y = -1$.