Calculate $\Delta T_b$ of a $0.45 \text{ m}$ solution of a nonvolatile solute in a solvent if the molal elevation constant of the solvent is $3.0 \text{ K kg mol}^{-1}$. (in $\text{ K}$)

The boiling point of water $(100\,^{\circ}C)$ becomes $100.52\,^{\circ}C$,if $3\,g$ of a non-volatile solute is dissolved in $200\,mL$ of water. The molecular weight of the solute is: (${K_b}$ for water is $0.6\,K\,kg\,mol^{-1}$)

What is the boiling point of a $0.5 \ m$ aqueous solution of sucrose if a $0.1 \ m$ aqueous solution of glucose boils at $100.16^{\circ} C$ (in $^{\circ} C$)?

$5 \ g$ of a non-volatile organic substance with molar mass $M_A$ is dissolved in $200 \ g$ of tetrahydrofuran. If $K_b$ is the molal elevation constant of tetrahydrofuran,then $\Delta T_b$ will be:

$A$ solution of $1$ molal concentration of a solute will have maximum boiling point elevation when the solvent is

$x \ g$ of urea (molar mass $60 \ g \ mol^{-1}$) is completely dissolved in $y \ g$ of pure water and the solution boiled at $373.202 \ K$. If the boiling point of pure water at $1.013 \ bar$ is $373.15 \ K$, then $x:y$ is $(K_b(H_2O) = 0.52 \ K \ kg \ mol^{-1})$