Calculate the consecutive oxidation numbers of $Br$ in $Br_3O_8$.

(N/A) The structure of $Br_3O_8$ shows three $Br$ atoms in a chain.
$1$. The terminal $Br$ atoms are each bonded to four oxygen atoms (three double bonds and one single bond,or equivalent resonance structures). Each terminal $Br$ atom is bonded to four $O$ atoms,resulting in an oxidation state of $+6$.
$2$. The central $Br$ atom is bonded to two oxygen atoms and two other $Br$ atoms. The oxidation state of the central $Br$ atom is $+4$.
Therefore,the consecutive oxidation numbers of $Br$ are $+6, +4, +6$.