(D) The correct option is $(D)$.Let the oxidation number of $S$ be $x$.In $Na_2SO_4$,the oxidation number of $Na$ is $+1$ and the oxidation number of

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(D) The correct option is $(D)$.Let the oxidation number of $S$ be $x$.In $Na_2SO_4$,the oxidation number of $Na$ is $+1$ and the oxidation number of $O$ is $-2$.Applying the sum rule: $2 \times (+1) + x + 4 \times (-2) = 0$.$2 + x - 8 = 0$.$x - 6 = 0$.$x = +6$.